Answer:
19.02 g
Step-by-step explanation:
dry gas mass of 3 moles of the
1. find out the identity of the gas
ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
First, we need to correct for the water vapor present in the gas sample. At 24◦C, the vapor pressure of water is 22 torr, so the total pressure in the sample is:
Ptotal = Pgas + Pwater vapor
706 torr = Pgas + 22 torr
Pgas = 684 torr
ideal gas law to get the number of moles of gas
n = PV/RT
where we use the corrected pressure and the temperature in Kelvin:
n = (684 torr x 4.5 L) / (0.0821 L·atm/mol·K x 297 K)
n = 0.883 mol
calculate the molar mass of the gas:
molar mass = mass / n
molar mass = 5.6 g / 0.883 mol
molar mass = 6.34 g/mol
calculate the mass of three moles of the gas:
mass = n x molar mass
mass = 3 mol x 6.34 g/mol
mass = 19.02 g
Therefore, the mass of three moles of the dry gas is 19.02 g
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