166k views
2 votes
If f(x)=x^6+5x^3-3, then what is the remainder when f(x) is divided by x+3

2 Answers

3 votes

Answer:

Explanation:

x+3

x=-3

f(-3)=-3^6+5(-3)^3-3

=729+5x(-27)-3

=729-135-3

=591

User Idrougge
by
7.3k points
3 votes

Explanation:

To find the remainder when f(x) = x^6 + 5x^3 - 3 is divided by x + 3, we can use synthetic division. The process of synthetic division involves the following steps:

1. Write down the coefficients of the polynomial in descending order of degree.

2. Bring down the first coefficient (in this case, 1) as the first entry in the division bar.

3. Multiply the divisor (x + 3) by the number in the division bar and write the result underneath the next coefficient.

4. Add the two values in the column to get the next entry in the division bar.

Repeat steps 3 and 4 until all coefficients have been processed.

Using these steps, we get:

-3 | 1 0 0 5 0 0 -3

| -3 9 -42 141 -423

-----------------------

1 -3 9 -37 141 -423

Therefore, the remainder when f(x) is divided by x + 3 is 1x^5 - 3x^4 + 9x^3 - 37x^2 + 141x - 423. We can also express this result in terms of the original polynomial f(x) as:

f(x) = (x + 3)(x^5 - 3x^4 + 9x^3 - 37x^2 + 141x - 423) + 1260

So, the remainder is 1260.

User Dilshad
by
7.6k points

No related questions found