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Use the zeros of the following quadratic to find the x value of the vertex.

y=x^2+2x-24
A. -2
B. -1
C. 2
D. -4

1 Answer

3 votes

Explanation:

We can find the x-value of the vertex of the quadratic function y = x^2 + 2x - 24 by first finding the zeros of the function using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 1, b = 2, and c = -24. Plugging in these values, we get:

x = (-2 ± sqrt(2^2 - 4(1)(-24))) / 2(1)

x = (-2 ± sqrt(100)) / 2

x = (-2 ± 10) / 2

So the zeros of the function are x = -6 and x = 4.

The x-value of the vertex is the midpoint between the zeros, which is simply the average of the two zeros:

x = (-6 + 4) / 2

x = -1

Therefore, the answer is B. -1.

User Paul Bele
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