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A bowling ball rolls at two rotations per second. What is its angular speed in degrees per second?

Given:

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Answer:

2 rotations / second = 2 * 360 deg / sec = 720 deg /sec

Note - 2 rot = 2 π * 2 = 4 π radians since 1 rotation = 2 π radians

User Shlomi Hassid
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