Question

Two old RSM students were standing ten feet apart when they ran in opposite directions with speeds of 180 feet per minute and 160 feet per minute respectively, how many minutes would pass before they were 1870 feet apart?

Answer 1

We can use the distance formula to solve this problem. Let d be the distance between the two students at time t (in minutes). Then:

d = 10 + 180t + 160t

d = 10 + 340t

We want to find the time it takes for the distance between them to reach 1870 feet, so we set d equal to 1870 and solve for t:

1870 = 10 + 340t

1860 = 340t

t = 5.47 minutes (rounded to two decimal places)

Therefore, it would take approximately 5.47 minutes before the two students were 1870 feet apart.