Question

A 3.0-kg sphere was moving at 25 m/s when it hit another object. This caused all KE to be converted into thermal energy. What was the increase in thermal energy?

I have been stuck on this problem for two hours. please help

Answer 1

ΔT=0.81

o

C

Step-by-step explanation:

As we know by energy conservation

All its kinetic energy will convert into thermal energy to raise its temperature

1

2

�

�

2

=

�

�

Δ

�

2

1

mv

2

=msΔT

now divide both sides by mass of the object

1

2

�

2

=

�

Δ

�

2

1

v

2

=sΔT

so change in temperature is given as

Δ

�

=

�

2

2

�

ΔT=

2s

v

2

Δ

�

=

2

5

2

2

×

387

ΔT=

2×387

25

2

Δ

�

=

0.8

1

�

�

ΔT=0.81

o

C

Answer 2

A 3.0-kg sphere was moving at 25 m/s when it hit another object. This caused all KE to be converted into thermal energy. What was the increase in thermal energy?

The initial kinetic energy of the sphere is given by:

KE = 0.5 * m * v^2

where m is the mass of the sphere and v is its velocity. Substituting the given values, we get:

KE = 0.5 * 3.0 kg * (25 m/s)^2

= 937.5 J

This is the initial kinetic energy of the sphere before it hit the other object. Since all of this energy is converted into thermal energy, the increase in thermal energy is simply equal to the initial kinetic energy, which is:

ΔE = KE = 937.5 J

Therefore, the increase in thermal energy is 937.5 Joules.