The point of intersection of the parabola y = x² + 2 and the line passing through the points (-2, 6) and (2, 6) are (-2, 6) and (2, 6).
How: To find the point of intersection of the parabola y = x² + 2 and the line passing through the points (-2, 6) and (2, 6), we need to set the y-values of the parabola and the line equal to each other, since the point of intersection must lie on both the parabola and the line.
Let's first find the equation of the line passing through the points (-2, 6) and (2, 6). Since the two points have the same y-coordinate, the line must be a horizontal line passing through y = 6. Therefore, the equation of the line is: y = 6
Now we can substitute y = 6 into the equation of the parabola and solve for x: 6 = x² + 2
Subtracting 2 from both sides, we get: 4 = x²
Taking the square root of both sides, we get: x = ±2
So the points of intersection are (-2, 6) and (2, 6).