To find the force that acts at 30° to the horizontal and pulls a weight of 25kg resting on a horizontal table, we need to use the concept of force equilibrium.
Let's start by drawing a diagram of the situation:
| /
| /
| /
30° |/
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| 25kg
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The weight of the 25kg object is acting vertically downwards, and we can resolve this force into two components: one acting horizontally and one acting vertically. The horizontal component of the weight is:
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Fh = 25kg x g x u = 25kg x 9.8m/s² x 0.4 = 98N
where u is the coefficient of friction between the object and the table.
The force acting at 30° to the horizontal can also be resolved into two components: one acting horizontally and one acting vertically. The horizontal component of this force is:
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Fh' = F x cos(30°) = F x 0.866
where F is the force acting at 30° to the horizontal.
Now we can apply force equilibrium in the horizontal direction:
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Fh' - Fh = 0 F x 0.866 - 98N = 0 F = 98N / 0.866 F = 113N
Therefore, the force that acts at 30° to the horizontal and pulls the weight of 25kg resting on a horizontal table is 113N.