Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

y(y + 5) = 750 and 750 - y(y - 5) = 0

Explanation:

let the length of the room be y,

l = y

w = y - 5 (width is 5 unit less than length)

Area = l . w

750 = y(y - 5)

750 - y(y - 5) = 0

Alternatively,

let width be = y

w = y

l = y + 5 (width is 5 feet less means length is 5 feet more than width)

Area = l . w

750 = y(y + 5)

Hopefully this answer helped you!