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Estimate the freezing point depression of

0.1 m C12H22011(aq). The freezing point
constant of water is 1.86 K kg/mol.
Answer in units of °C.

User Seanieb
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1 Answer

5 votes

Step-by-step explanation:

To calculate the freezing point depression, we need to use the formula:

ΔTf = Kf * m

Where ΔTf is the freezing point depression, Kf is the freezing point constant of water, and m is the molality of the solute.

First, we need to calculate the molality (m) of the solution:

molality = moles of solute / mass of solvent in kg

Since we have 0.1 moles of C12H22011 in 1 kg of water (assuming the density of water is 1 kg/L), we have:

molality = 0.1 mol / 1 kg = 0.1 m

Now, we can plug in the values into the formula:

ΔTf = Kf * m ΔTf = 1.86 K kg/mol * 0.1 mol = 0.186 K

Therefore, the freezing point depression of the solution is 0.186 °C.

User AHegde
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8.0k points