Question

According to a survey, the probability that a randomly selected worker primarily drives a van to work is 0.868. The probability that a randomly selected worker primarily takes public transportation to work is 0.044.

Answer 1

the probability that a randomly selected worker does neither of these activities is 0.088 or 8.8%.

Explanation:

We can use the fact that the sum of probabilities of all possible outcomes must equal 1 to calculate the probability of a randomly selected worker doing neither of these activities.

Let A be the event that a randomly selected worker primarily drives a van to work, and B be the event that a randomly selected worker primarily takes public transportation to work. Then, the probability of neither event happening (i.e., a worker who does not primarily drive a van to work and does not primarily take public transportation to work) is:

P(neither A nor B) = 1 - P(A) - P(B)

Substituting the given probabilities, we get:

P(neither A nor B) = 1 - 0.868 - 0.044 = 0.088

Therefore, the probability that a randomly selected worker does neither of these activities is 0.088 or 8.8%.