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If ab=8 and a^2+b^2=16, what is the value of (a+b)^2

User Param
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1 Answer

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Explanation:

well, do the multiplication of the square and compare the parts of the expression.

(a + b)² = (a + b)(a + b) = a² + ab + ab + b² =

= a² + 2ab + b² = a² + b² + 2ab

a² + b² = 16

ab = 8

so, we have

(a+b)² = 16 + 2×8 = 16 + 16 = 32

User Marco Leung
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