Answer:
0.6689 moles of Mg3(PO4)2
Step-by-step explanation:
To calculate the number of moles of Mg3(PO4)2 in a beaker with 175.87 g of Mg3(PO4)2, we need to use the formula:
moles = mass / molar mass
The molar mass of Mg3(PO4)2 can be calculated by adding the atomic masses of all the atoms in the compound:
Mg3(PO4)2 = 3(Mg) + 2(P) + 8(O)
Mg3(PO4)2 = (3 x 24.31 g/mol) + (2 x 30.97 g/mol) + (8 x 16.00 g/mol)
Mg3(PO4)2 = 262.86 g/mol
Now we can plug in the values we have:
moles = 175.87 g / 262.86 g/mol
moles = 0.6689 mol
Therefore, there are 0.6689 moles of Mg3(PO4)2 in the beaker with 175.87 g of Mg3(PO4)2.