Question

What is the vertex for y = x2 - 4x

Answer 1

vertex is at (2, -4)

Step-by-step explanation:

`\bold{x}_{\bold{vertex}}=-(b)/(2a);\bold{y}_{\bold{vertex}} =f\huge \text{(}-(2)/(ba)\huge \text{)}` given the equation in the standard form of

`ax^2+bx+c`

Given :

`y=x^2-4x+0`

`a=1, \ b=-4, \ c=0`

`\bold{x}_{\bold{vertex}}=(-(-4))/(2*1) =(4)/(2) =2`

`\bold{y}_{\bold{vertex}}=f(2)=(2)^2-4(2)=4-8=-4`

`\bold{Vertex}:(x,y)=(2,-4)`