Answer:
The maximum coefficient of static friction required to pull the box will be 0.4.
Step-by-step explanation:
We have given a box of mass 2 kg and Force of 50 N. (g=10m/s)
As we know,
Coefficient of static friction: μ = F/N (I)(F=ma, a= g)
Putting value in equation (I), we get
μ= mg/
μ=2×10/50
μ=0.4