Answer:
Explanation:
You want to solve the following relations for the cost of a pair of jeans and the cost of a blouse.
- 3 jeans + 6 blouses for $120
- 2 jeans + 5 blouses for $90
Matrix method
The equations can be represented by the augmented matrix ...
![\left[\begin{array}c3&6&120\\2&5&90\end{array}\right]](https://img.qammunity.org/2024/formulas/mathematics/high-school/evwo2jq4psdy0dxjiq51gw5bl7udrslot4.png)
Reducing this to "reduced row-echelon form" tells you the prices:
- a pair of jeans: $20
- a blouse: $10
Graphing
We can graph the two equations, using x and y for the prices of jeans and a blouse, respectively. The point of intersection of the two lines is ...
(x, y) = (20, 10)
This tells us the prices are ...
- a pair of jeans: $20
- a blouse: $10
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Additional comment
There are algebraic methods of solution as well. In general, we find them more tedious, especially for a system of equations like this where the coefficients are not simple multiples of one another.
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