Answer:
Each child plays jacks for 6 minutes.
Explanation:
♦ To solve this problem, we need to first figure out how many groups of three children we can make with five children. We can do this by dividing the total number of children (5) by the number of children in each group (3):
5 ÷ 3 = 1 with a remainder of 2
♦ This means we can make one group of three children and have two children left over who cannot play at the same time as the other children. We can have these two children take turns playing with one of the children from the group of three, so that there are three children playing at a time.
♦ Now, we know that the three children in each group will play for the same amount of time. We also know that they will be playing for a total of 30 minutes. So, we need to figure out how long each group will play for.
If we divide 30 minutes by the number of groups we have (1), we get:
30 ÷ 1 = 30
♦ So, the one group of three children will play for 30 minutes. But we also need to factor in the two children who are playing with them. If we divide the 30 minutes by the total number of children playing (5), we get:
30 ÷ 5 = 6
This means that each child plays jacks for 6 minutes.
To summarize, 5 children take turns playing jacks so that each child plays for the same amount of time. We can make one group of three children and have two children left over who take turns playing with one of the children from the group of three. Each group of three children plays for 30 minutes, and since there are a total of 5 children playing, each child plays jacks for 6 minutes.