Question

Solve for x.

x² + 6x + 9 = 12
0 x = -9 + 2√3
0 x =
-9 ± 4√3
0 x =
−3 ± 4√3
0 x = −3+2√3

Answer 1

`x1 = - 3 - 2 √(3)`

`x2 = - 3 + 2 √(3)`

Explanation:

`{x}^(2) + 6x + 9 = 12`

`{x}^(2) + 6x + 9 - 12 = 0`

`{x}^(2) + 6x - 3 = 0`

a = 1, b = 6, c = -3

`d = {b}^(2) - 4ac = {6}^(2) - 4 * 1 * ( - 3) = 36 + 12 = 48 > 0`

`x1 = ( - b - √(d) )/(2a) = ( - 6 - √(48) )/(2 * 1) ( - 6 - 4 √(3) )/(2) = - 3 - 2 √(3)`

`x2 = ( - b + √(d) )/(2a) = ( - 6 + √(48) )/(2 * 1) = ( - 6 + 4 √(3) )/(2) = - 3 + 2 √(3)`

Answer 2

Explanation:

= x^2 + 6x - 3 = 0

Are you familiar with the Quadratic Formula?

a = 1 b = 6 c = -3

then x = -3 ± 2
`√(3)`