Question

4 CFL of 15 watt and heater of 1000 watt are used for 90 min in a flat, What will be the reading of the electric -meter of that flat after 30 days.​

Answer 1

Step-by-step explanation:

4CFl 15W each

therefore power is 60W = 60×10^-3 kW

and heater = 1000 W = 1kW

total power = 1.06 kW

therefore, electrical energy = 1.06 × 90/60 = 1.59 kWh.

so, monthly electric meter reading = 1.59 × 30 = 47.7 kWh.

hope this helps.

Answer 2

hey, The answer is 47.7 unit

Step-by-step explanation:

Solu,

Power of CFl (P)= 15×4/1000

=0.06 KW

No of CFL(N) =4

Time(T) = 90/60

=1.5

Now according to question after 30 days=1.5×30

=45 hour

Power of heater(P) =1000/1000

=1 KW

For CFL

we know,.

EC by CFL(EC1) =P×T

=0.06 × 45

=2.7 unit

For heater

EC consumed by heater (EC2) =P×T

=1 ×45

=45 unit

:. Total unit consumed= EC1 +EC2

= 2.7+ 45

= 47.7 unit

:.The reading of flat after 30 days will be 47.7 unit

Comment if wrong

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