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Value of acceleration due to gravity at surface of the heavenly body, the value of acceleration due to gravity will be 2.25 m/s? Calculate by Using suitable formula.​

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Answer:

R = 7.02 × 10^6 meters

Step-by-step explanation:

To calculate the value of acceleration due to gravity at the surface of a heavenly body with a given value, we can use the formula:

g = G*M/R^2

Where:

g = acceleration due to gravity at the surface

G = gravitational constant (6.67430 × 10^-11 m^3 kg^-1 s^-2)

M = mass of the heavenly body

R = radius of the heavenly body

Substituting the given value of acceleration due to gravity (g = 2.25 m/s^2) and assuming that the mass of the heavenly body is known (let's say M = 6.0 × 10^24 kg), we can rearrange the formula to solve for the radius R:

R = sqrt(G*M/g)

Plugging in the values, we get:

R = sqrt((6.67430 × 10^-11 m^3 kg^-1 s^-2) * (6.0 × 10^24 kg) / (2.25 m/s^2))

Simplifying the expression, we get:

R = 7.02 × 10^6 meters

Therefore, the radius of the heavenly body would be approximately 7.02 × 10^6 meters, assuming a mass of 6.0 × 10^24 kg and an acceleration due to gravity at the surface of 2.25 m/s^2.

Note that this is a hypothetical scenario as the value of acceleration due to gravity varies from planet to planet and other celestial bodies.

User Olinasc
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Final answer:

The value of acceleration due to gravity at the surface of a heavenly body can be calculated using the formula g = G * (M / R^2), where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the heavenly body, and R is the radius of the heavenly body.

Step-by-step explanation:

The value of acceleration due to gravity at the surface of a heavenly body can be calculated using the formula:

g = G * (M / R^2)

where:

  • g is the acceleration due to gravity
  • G is the gravitational constant (approximately 6.674 × 10^-11 N m^2 / kg^2)
  • M is the mass of the heavenly body
  • R is the radius of the heavenly body

For example, if the mass of the heavenly body is 2 times the mass of the Sun and the radius is half the radius of Earth, we can calculate:

M = 2*1.989 × 10^30 kg (mass of the Sun)

R = 0.5 * 6,371 km (radius of Earth)

Substituting these values into the formula, we get:

g = 6.674 × 10^-11 N m^2 / kg^2 * (2*1.989 × 10^30 kg) / (0.5 * 6,371 km)^2

Simplifying the equation will give us the value of acceleration due to gravity at the surface of the heavenly body.

User Amro Younes
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