Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

The equations that can be used to solve for y, the length of the room, are:y(y + 5) = 750y2 – 5y = 750(y + 25)(y – 30) = 0Option 1 represents the area of the rectangular room as the product of the length and width, where the width is 5 feet less than the length.Option 2 is obtained by rearranging option 1 and setting it equal to zero.Option 3 represents the factors of 750, where one factor is y + 25 and the other is y – 30, based on the information that the width is 5 feet less than the length.