Step-by-step explanation:
The electrical potential energy change is given by:
ΔPE = qΔV
where ΔV is the potential difference between the initial and final positions of the charge q.
In this case, the charge q is 350 mC, and the initial position is 2.0 m above the ground, where the potential energy is PE = qV. The final position is the ground, where the potential energy is zero.
The potential difference between the initial and final positions can be found using the electric field strength E and the distance d traveled by the charge:
ΔV = Ed
In this case, the charge travels in the direction of the field, so the potential difference is:
ΔV = Ed = (1.0 x 10^6 N/C) x (2.0 m) = 2.0 x 10^6 V
Therefore, the electrical potential energy change is:
ΔPE = qΔV = (350 x 10^-3 C) x (2.0 x 10^6 V) = 700 J
So the change in electrical potential energy in a lightning bolt with the given parameters is 700 Joules.