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Pls Help Id rlly appreciate it thx!!

Pls Help Id rlly appreciate it thx!!-example-1
User Gowsik
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1 Answer

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Step-by-step explanation:

The electrical potential energy change is given by:

ΔPE = qΔV

where ΔV is the potential difference between the initial and final positions of the charge q.

In this case, the charge q is 350 mC, and the initial position is 2.0 m above the ground, where the potential energy is PE = qV. The final position is the ground, where the potential energy is zero.

The potential difference between the initial and final positions can be found using the electric field strength E and the distance d traveled by the charge:

ΔV = Ed

In this case, the charge travels in the direction of the field, so the potential difference is:

ΔV = Ed = (1.0 x 10^6 N/C) x (2.0 m) = 2.0 x 10^6 V

Therefore, the electrical potential energy change is:

ΔPE = qΔV = (350 x 10^-3 C) x (2.0 x 10^6 V) = 700 J

So the change in electrical potential energy in a lightning bolt with the given parameters is 700 Joules.

User Cetcet
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