Answer:
-6.3158 x 10^-6 C.
Step-by-step explanation:
Given:
Distance travelled by the particle, d = 800.0 cm = 8.00 m
Strength of the electric field, E = 95 N/C
Change in electrical potential energy, ΔU = -4.8 x 10 J
Unknown:
Charge of the particle, q
Formula:
The change in electrical potential energy ΔU of a charged particle with charge q moving a distance d in an electric field of strength E is given by:
ΔU = qEd
The charge q of the particle is given by:
q = ΔU / Ed
Solution:
Substituting the given values in the formula, we get:
q = ΔU / Ed
q = (-4.8 x 10 J) / (95 N/C x 8.00 m)
q = -6.3158 x 10^-6 C
Therefore, the particle's charge is -6.3158 x 10^-6 C.