Answer:
15.6 grams of baking soda can produce 6.124 grams of water.
Explanation:
The chemical equation for the reaction of baking soda (sodium bicarbonate) with vinegar (acetic acid) is:
NaHCO3 + CH3COOH → CO2 + H2O + NaCH3COO
From the balanced equation, we can see that for every 1 mole of NaHCO3 reacted, 1 mole of H2O is produced.
The molar mass of NaHCO3 is:
Na: 22.99 g/mol
H: 1.01 g/mol
C: 12.01 g/mol
O: 3 x 16.00 g/mol = 48.00 g/mol
Molar mass of NaHCO3 = 22.99 + 1.01 + 12.01 + 48.00 = 84.01 g/mol
Therefore, 1 mole of NaHCO3 has a mass of 84.01 grams.
To find the number of moles of NaHCO3 in 15.6 grams, we divide by the molar mass:
15.6 g / 84.01 g/mol = 0.1855 moles
Since the reaction produces 1 mole of H2O for every mole of NaHCO3, we can expect to produce 0.1855 moles of water.
The molar mass of water is:
H: 1.01 g/mol
O: 2 x 16.00 g/mol = 32.00 g/mol
Molar mass of H2O = 1.01 + 32.00 = 33.01 g/mol
Therefore, 1 mole of H2O has a mass of 33.01 grams.
To find the mass of water produced, we multiply the number of moles by the molar mass:
0.1855 moles × 33.01 g/mol = 6.124 grams of water
So, 15.6 grams of baking soda can produce 6.124 grams of water.