Answer:
we need 0.528 moles of Fe2(SO4)2 to react with 123.5 g of NaCl.
Step-by-step explanation:
To solve this problem, we need to first write the balanced chemical equation for the reaction between Fe2(SO4)2 and NaCl:
Fe2(SO4)2 + 4NaCl → 2FeCl2 + Na2SO4
From this equation, we can see that 1 mole of Fe2(SO4)2 reacts with 4 moles of NaCl.
Next, we need to calculate the number of moles of NaCl that we have, using the formula:
moles = mass / molar mass
The molar mass of NaCl is:
1 Na atom = 22.99 g/mol
1 Cl atom = 35.45 g/mol
So, the molar mass of NaCl is:
22.99 + 35.45 = 58.44 g/mol
Using the formula, we have:
moles of NaCl = 123.5 g / 58.44 g/mol
moles of NaCl = 2.113 mol
Now, we can use the mole ratio between Fe2(SO4)2 and NaCl to calculate the number of moles of Fe2(SO4)2 needed:
moles of Fe2(SO4)2 = moles of NaCl / 4
moles of Fe2(SO4)2 = 2.113 mol / 4
moles of Fe2(SO4)2 = 0.528 mol