Question

A cliff diver on an alien planet dives of 32 meter tall cliff and lands in a sea of hydrochloric acid 1.20 seconds later. Assuming that the extra terrestrial's initial speed was zero , what is the free fall acceleration of this strange world?

Answer 1

Step-by-step explanation:

We can use the kinematic equation for free fall motion to solve for the acceleration of the alien planet:

h = (1/2)gt^2

where h is the height of the cliff, g is the acceleration due to gravity on the planet, and t is the time it takes for the diver to fall.

Plugging in the given values, we get:

32 = (1/2)g(1.20)^2

Simplifying:

32 = 0.72g

g = 44.44 m/s^2

Therefore, the free fall acceleration on this strange world is 44.44 m/s^2.