Answer:
0.1518 moles of CaCO3 can be produced.
Step-by-step explanation:
The balanced chemical equation for the reaction between calcium bicarbonate and calcium hydroxide is:
Ca(HCO3)2 + Ca(OH)2 → 2CaCO3 + 2H2O
From this equation, we can see that 1 mole of Ca(HCO3)2 produces 2 moles of CaCO3.
The molar mass of Ca(HCO3)2 is:
1 Ca atom = 40.08 g/mol
2 H atoms = 2.02 g/mol
2 CO3 molecules = 2 x 60.01 g/mol = 120.02 g/mol
So, the molar mass of Ca(HCO3)2 is:
40.08 + 2.02 + 120.02 = 162.12 g/mol
To find the number of moles of Ca(HCO3)2 in 12.3 g, we use the formula:
moles = mass / molar mass
moles = 12.3 g / 162.12 g/mol
moles = 0.0759 mol
According to the balanced equation, 1 mole of Ca(HCO3)2 produces 2 moles of CaCO3. Therefore, 0.0759 moles of Ca(HCO3)2 will produce:
moles of CaCO3 = 2 x moles of Ca(HCO3)2
moles of CaCO3 = 2 x 0.0759
moles of CaCO3 = 0.1518 mol
Therefore, 0.1518 moles of CaCO3 can be produced.