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If 50000kg of water poorevery 5second over the is avary full of height 50.What Power could be avilable​

1 Answer

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Answer:

Assuming that the question is about power generation using the pouring water, we can use the following formula to calculate the power generated:

Power = Mass flow rate x g x height

where,

Mass flow rate = mass of water poured per second

g = acceleration due to gravity (9.81 m/s^2)

height = height of the dam (50 m)

Given, mass of water poured every 5 seconds = 50000 kg

Therefore, mass flow rate = 50000 kg / 5 s = 10000 kg/s

Substituting these values in the formula, we get:

Power = 10000 kg/s x 9.81 m/s^2 x 50 m

Power = 4,905,000 Watts or approximately 4.9 MW

Therefore, the available power would be approximately 4.9 MW.

User Tomlogic
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