Question

A ball moving at 60 m/s toward a wall to its right gets back at a speed of 40m/s after striking the wall . if the mass of the ball of

3kg . what is the change in momentum

Answer 1

-300 kg*m/s

Step-by-step explanation:

The velocity of the ball before the collision is +60 m/s, and the velocity after the collision is -40 m/s (since the ball bounces back in the opposite direction). The mass of the ball is 3 kg.

The momentum of the ball before the collision can be calculated as:

p1 = mv1 = 3 kg * 60 m/s = 180 kgm/s

The momentum of the ball after the collision can be calculated as:

p2 = mv2 = 3 kg * (-40 m/s) = -120 kgm/s

The change in momentum is then:

Δp = p2 - p1 = (-120 kgm/s) - (180 kgm/s) = -300 kg*m/s

Note that the negative sign indicates that the momentum of the ball has decreased (since it bounced back in the opposite direction), and the magnitude of the change in momentum is 300 kg*m/s.