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If there are 10 grams of CuCl, and 6 grams of NaNO, which is the limiting reactant?​

1 Answer

3 votes

Answer:

NaNO3

Step-by-step explanation:

To determine the limiting reactant, we need to compare the amounts of each reactant present and calculate the amount of product that can be formed from each.

The balanced chemical equation for the reaction between CuCl and NaNO3 is:

2 CuCl + 2 NaNO3 → Cu(NO3)2 + 2 NaCl

Using the molar masses of CuCl and NaNO3, we can convert the given masses to moles:

moles of CuCl = 10 g / 134.45 g/mol = 0.0745 mol

moles of NaNO3 = 6 g / 84.99 g/mol = 0.0706 mol

According to the balanced equation, 2 moles of CuCl react with 2 moles of NaNO3 to produce 1 mole of Cu(NO3)2. Therefore, the theoretical yield of Cu(NO3)2 is:

theoretical yield = 0.0745 mol / 2 mol x (1 mol / 2 mol) = 0.0186 mol

and

theoretical yield = 0.0706 mol / 2 mol x (1 mol / 2 mol) = 0.0177 mol

Since the theoretical yield of Cu(NO3)2 is smaller from NaNO3, NaNO3 is the limiting reactant.

Therefore, NaNO3 is the limiting reactant in this reaction.

User Kostas Pelelis
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