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How many oxygen atoms are in 1.5x10^-5 moles of sulfur dioxide?

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Answer:

Sulfur dioxide has the chemical formula SO2, which indicates that it contains 1 sulfur atom and 2 oxygen atoms. To calculate the number of oxygen atoms in 1.5x10^-5 moles of sulfur dioxide, we can use the following steps:

Determine the number of moles of SO2:

moles of SO2 = 1.5x10^-5 mol

Use the balanced chemical equation for SO2 to determine the mole ratio of O atoms to SO2:

SO2 + O2 → 2SO3

For every 1 mole of SO2, there are 2 moles of O atoms.

Multiply the number of moles of SO2 by the mole ratio of O atoms to SO2 to obtain the number of moles of O atoms:

moles of O atoms = moles of SO2 x (2 moles of O atoms / 1 mole of SO2)

moles of O atoms = 1.5x10^-5 mol x 2

moles of O atoms = 3x10^-5 mol

Finally, convert the number of moles of O atoms to the number of atoms:

number of O atoms = moles of O atoms x Avogadro's number

number of O atoms = 3x10^-5 mol x 6.022x10^23 atoms/mol

number of O atoms = 1.8066x10^19 atoms

Therefore, there are approximately 1.8x10^19 oxygen atoms in 1.5x10^-5 moles of sulfur dioxide.

Step-by-step explanation:

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