Answer:
The maximum energy stored in the flywheel is given by the formula:
E = 1/2 * I * w^2
where E is the energy stored, I is the moment of inertia, and w is the angular velocity of the flywheel.
We are given E = 3.9 MJ and w = 10000 rev/min. First, we need to convert w to radians per second:
w = 10000 rev/min * (2*pi rad/rev) / (60 s/min) = 1047.2 rad/s
Substituting the given values into the formula, we get:
3.9 MJ = 1/2 * I * (1047.2 rad/s)^2
Solving for I, we get:
I = 3.9 MJ / (1/2 * (1047.2 rad/s)^2)
= 8.15 kg m^2
Therefore, the moment of inertia of the flywheel is 8.15 kg m^2.