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What is the surface area of this right triangular prism? Enter your answer in the box. in² Right triangular prism. The height of the prism is labeled 4 in. The base of the prism is a triangle with sides labeled 5 in., 5 in., and 8 in. There is a dashed line from the vertex of the triangle perpendicular to the 8 in. side that is labeled 3 in.

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Answer:

The area of each triangular face is (1/2)bh, where b is the base and h is the height of the triangle.The area of the rectangular face is simply the product of its length, 8 in., and height, 4 in.Using the Pythagorean Theorem, we can find the height of the triangle:h^2 = 5^2 - 3^2 = 16h = √16 = 4 in.So the area of each triangular face is (1/2)(5 in.)(4 in.) = 10 in².The area of the rectangular face is (8 in.)(4 in.) = 32 in².Therefore, the total surface area is 2(10 in²) + 32 in² = 52 in².So the surface area of the right triangular prism is 52 square inches.

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