Answer:
Total surface area = 1.8985 m²/mailbox × 1937 mailboxes = 3673.26 m²
Rounding up to the next square meter, the company will need 3674 square meters of aluminum to make these mailboxes.
Explanation:
Based on the given dimensions, the surface area of one mailbox can be calculated as follows:
Surface area of the rectangular box: 2(0.6 m × 0.4 m) + 2(0.6 m × 0.55 m) + 2(0.4 m × 0.55 m) = 1.32 m²
Surface area of the half-cylinder top: (0.6 m × 0.55 m × 3.14) / 2 = 0.5785 m²
Total surface area of one mailbox = 1.32 m² + 0.5785 m² = 1.8985 m²
To make 1937 mailboxes, the total surface area of aluminum needed can be calculated by multiplying the surface area of one mailbox by the number of mailboxes:
Total surface area = 1.8985 m²/mailbox × 1937 mailboxes = 3673.26 m²
Rounding up to the next square meter, the company will need 3674 square meters of aluminum to make these mailboxes.