Answer:
Therefore, the surface area of the red sphere is approximately 373.7 square inches, rounded to the nearest tenth.
Explanation:
Since the spheres are similar, their surface areas are proportional to the square of their radii.
Let r be the radius of the red sphere, and let R be the radius of the blue sphere. Then:
S_red / S_blue = (r / R)²
We know that S_blue = 4071.5, and we know that the blue sphere has a radius of 24 inches. Therefore:
S_red / 4071.5 = (r / 24)²
To find S_red, we need to solve for r:
(r / 24)² = S_red / 4071.5
r / 24 = sqrt(S_red / 4071.5)
r = 24 * sqrt(S_red / 4071.5)
Now we can substitute this expression for r into the equation S_red / S_blue = (r / R)²:
S_red / 4071.5 = (24 * sqrt(S_red / 4071.5) / R)²
S_red / 4071.5 = (576 * S_red / (4071.5 * R²))
S_red = (576 / 4071.5) * S_red * R²
Dividing both sides by S_red and simplifying:
1 = 576 / 4071.5 * R²
R² = 576 / 4071.5
R = sqrt(576 / 4071.5) = 0.3051
So the radius of the blue sphere is approximately 0.3051 times the radius of the red sphere. Therefore:
S_red / S_blue = (R / r)² = (1 / 0.3051)² = 10.89
S_red = 4071.5 / 10.89 = 373.7
Therefore, the surface area of the red sphere is approximately 373.7 square inches, rounded to the nearest tenth.