Question

A tetherball on a 1.55-m rope is struck so that it goes into circular motion in a horizontal plane, with the rope making a 12.0° angle to the horizontal.

Answer 1

To solve this problem, we can use the following equation:

T = 2π√(r/g)

where T is the period (time for one complete revolution), r is the length of the rope, and g is the acceleration due to gravity.

First, we need to find the length of the rope. We can use trigonometry to do this:

sin(12°) = r/1.55m

r = 1.55m * sin(12°) = 0.319m

Next, we need to find g. We can use the value of 9.81 m/s^2 for the acceleration due to gravity.

Now we can plug in our values and solve for T:

T = 2π√(0.319m/9.81 m/s^2)

T ≈ 0.807 s

Therefore, the period of the tetherball's motion is approximately 0.807 seconds.