8.9k views
5 votes
F(x)=-2^2-4x+1. write the equation in the form f(x)=a(x-h)^2+k. then give the vertex of its graph.

User Berke
by
7.8k points

2 Answers

5 votes

Answer: The vertex of the parabola is at the point (-1, 3).

User Latika
by
8.4k points
6 votes

Answer:

Starting with the given function:

f(x) = -2x^2 - 4x + 1

To write this in the form f(x) = a(x-h)^2 + k, we need to complete the square. We can do this by adding and subtracting a constant term that will make the expression a perfect square trinomial.

f(x) = -2(x^2 + 2x) + 1

f(x) = -2(x^2 + 2x + 1) + 2 + 1 (adding and subtracting 1)

f(x) = -2(x + 1)^2 + 3

Therefore, the equation in the form f(x) = a(x-h)^2 + k is f(x) = -2(x + 1)^2 + 3, where a = -2, h = -1, and k = 3.

The vertex of the parabola is at the point (-1, 3).

User Kovalsky Dmitryi
by
7.8k points