Question

If a box has a frictional force of 20 N

and the coefficient of friction
between the box and surface is
μ=0.3, what is the force on the
Normal?

Answer 1

Step-by-step explanation:

F - UkFN = ma Note Friction opposes the motion thus subtract friction from the force. Uk is the coefficient of kinetic friction. FN is the normal force equal to mg since I assume it’s on a horizontal surface.

F - Ukmg = ma (Note mass does NOT cancel.)

20 N - 0.3 (4kg)*(9,8 m/s^2) = 4kg*(a