Question

A swimming pool contains 6.8 × 10³ gallons of water. The pool is leaking

at a rate of 12-1 gallons per second. How many hours will it take for all of
the water to leak out of the pool?

Answer 1

Explanation:

We can start by using the leak rate to determine how much water is lost in one second:

12-1 gallons/second

Next, we can set up an equation to determine how many seconds it will take for all of the water to leak out of the pool:

6.8 × 10³ gallons / (12-1 gallons/second) = x seconds

Simplifying the expression on the left-hand side, we get:

6.8 × 10³ gallons / (12-1 gallons/second) = 6.8 × 10³ gallons / 11 gallons/second

= 618.18 seconds

Therefore, it will take 618.18 seconds for all of the water to leak out of the pool. To convert this to hours, we can divide by the number of seconds in an hour:

618.18 seconds / 3600 seconds/hour ≈ 0.172 hours

Therefore, it will take approximately 0.172 hours, or about 10.3 minutes, for all of the water to leak out of the pool.

Answer 2

If a swimming pool contains 6.8 × 10³ gallons of water and is leaking at a rate of 12-1 gallons per second, then it will take (6.8 × 10³) / (12-1) = 6800 / 11 ≈ 618.18 seconds for all of the water to leak out of the pool. Since there are 3600 seconds in an hour, it will take approximately 618.18 / 3600 ≈ 0.17 hours or about 10 minutes for all of the water to leak out of the pool.

Explanation: