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A gas is compressed from 2 liters to 50 mL and the resulting pressure is 300 kPa what was the original pressure?

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Answer:

P1 = 7.5 kPa

Explanation:

We can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when temperature is constant. Mathematically, Boyle's Law can be expressed as:

P1 x V1 = P2 x V2

where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.

Substituting the given values, we get:

P1 x 2 L = 300 kPa x 50 mL

Converting 2 liters to milliliters, we have:

P1 x 2000 mL = 300 kPa x 50 mL

Simplifying, we get:

P1 = (300 kPa x 50 mL) / 2000 mL

P1 = 7.5 kPa

Therefore, the original pressure was 7.5 kPa.
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