Question

. Triangle JKL with vertices J(-4, -1), K(0, -5), and I(-2, -8): 90° counterclockwise​

Answer 1

To rotate a point counterclockwise by 90 degrees, we can use the following formula:

(x', y') = (-y, x)

where (x, y) is the original point and (x', y') is the rotated point.

So, applying this formula to each vertex of triangle JKL:

J(-4, -1) rotates to J' = (1, -4)

K(0, -5) rotates to K' = (5, 0)

I(-2, -8) rotates to I' = (8, 2)

Therefore, the vertices of the triangle J'K'I' after a 90-degree counterclockwise rotation are J'(1, -4), K'(5, 0), and I'(8, 2).