Question

PLEASE ANSWER 50 POINTS!!!!!!!!

What mass of H2 forms from 81 g AI?
2AI + 6HCI --> 2AICI3 + 3H2
AI: 27 g/mol H2: 2 g/mol

Answer 1

9 grams

Step-by-step explanation:

Assuming that HCl is excess

moles of the reactant aluminum = 81/27 = 3 moles

By organizing the given data with ratios:

2AI + 6HCI --> 2AICI3 + 3H2

(2) : 6 : 2 : 3

(3) : -- : -- : ?

Part value = 3/2 = 1.5

yielded moles of H2 = 1.5 * 3 = 4.5 moles

mass produced of H2 = 4.5 * 2 = 9 grams

If you have any question about this answer, just write it in the comments