Since the function is already in standard form (ax^2 + bx + c form) you don't have to change anything and simply rewrite it.
For the vertex, if you have a quadratic function in standard form -b/2a is the x value of the vertex.
-b/2a = -4/(2(2)) = -1
Since we now know the x-value of the vertex we can plug it into the function to find the corresponding y-value.
h(-1) = 2(-1)^2 + 4(-1) - 10 = -12
So, the vertex is at (-1,-12)