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What is y=-2(x+4)^2-11 in standard form

1 Answer

4 votes

Answer:

y=2x^2+16x+11

Explanation:

Standard form is y=ax^2+bx+c.

In order to write this polynomial in standard form, we need to simplify and then arrange the terms in decreasing order.

Rewrite (x+4)^2 as (x+4)(x+4) and then expand using FOIL.

y=2(x⋅x+x⋅4+4x+4⋅4)−21

Simplify.

y=2(x^2+8x+16)−21

Apply the distributive property and simplify.

y=2x^2+2(8x)+2⋅16−21

y=2x^2+16x+32−21

y=2x^2+16x+11

Therefore,

y=2x^2+16x+11

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