Answer:
Explanation:
In ∆PQR, you have the angle relations P-Q = 42 and Q-R = 21. You want the measures of all the angles.
Angle sum
The sum of the angles in the triangle is 180°. Using the given relation between P and Q, we have ...
P = Q +42
Using the given relation between Q and R, we have ...
R = Q -21
Then the angle sum is ...
P +Q +R = 180
(Q +42) +Q +(Q -21) = 180 . . . . . . substitute for P and R
3Q +21 = 180 . . . . . . . . . . . . . collect terms
Q +7 = 60 . . . . . . . . . . . . divide by 3
Q = 53 . . . . . . . . . . . subtract 7
P = Q +42 = 95
R = Q -21 = 32
The angles P, Q, R are 95°, 53°, and 32°, respectively.