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PLEASE HELP!!!!! During the basketball game, the cheerleaders sold 50 scratch tickets. There are 2 winning scratch tickets and 48 that are not winners. What is the probability that neither the first nor the second scratch ticket SOLD are winners?

PLEASE HELP!!!!! During the basketball game, the cheerleaders sold 50 scratch tickets-example-1
User Akif
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2 Answers

1 vote

Answer:

Explanation:

90%

i took the test

User Wlo
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The probability that neither the first nor the second scratch ticket sold are winners can be found by multiplying the probability of the first ticket not being a winner (48/50) by the probability of the second ticket not being a winner (47/49) since there are now 49 tickets remaining after the first one is sold. Thus, the probability is:(48/50) x (47/49) = 0.9024 or approximately 90.24%Therefore, the closest answer choice is 90.

User Cdeerinck
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