The probability that neither the first nor the second scratch ticket sold are winners can be found by multiplying the probability of the first ticket not being a winner (48/50) by the probability of the second ticket not being a winner (47/49) since there are now 49 tickets remaining after the first one is sold. Thus, the probability is:(48/50) x (47/49) = 0.9024 or approximately 90.24%Therefore, the closest answer choice is 90.