Question

Chemistry needs help please

Answer 1

To determine the theoretical yield of NaOH, we need to use stoichiometry to find the mole ratio between Ca(OH)2 and NaOH in the balanced chemical equation.

The balanced chemical equation is:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

The mole ratio between Ca(OH)2 and NaOH is 1:2, which means that for every 1 mole of Ca(OH)2, 2 moles of NaOH will be produced.

First, we need to convert the given mass of Ca(OH)2 to moles:

5.6 g Ca(OH)2 x (1 mol Ca(OH)2 / 74.09 g Ca(OH)2) = 0.0756 mol Ca(OH)2

Using the mole ratio from the balanced equation, we can calculate the theoretical yield of NaOH:

0.0756 mol Ca(OH)2 x (2 mol NaOH / 1 mol Ca(OH)2) x (40.00 g NaOH / 1 mol NaOH) = 6.05 g NaOH

Therefore, the theoretical yield of NaOH is 6.05 g. The answer is option C.

Answer 2

First, we need to balance the chemical equation:Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3Now we can use stoichiometry to find the theoretical yield of NaOH. The balanced equation tells us that 1 mole of Ca(OH)2 produces 2 moles of NaOH. The molar mass of Ca(OH)2 is:40.08 g/mol (Ca) + 2(1.01 g/mol)(H) + 2(16.00 g/mol)(O) = 74.10 g/molSo, 5.6 g of Ca(OH)2 is equal to:5.6 g / 74.10 g/mol = 0.0755 molAccording to the balanced equation, 1 mole of Ca(OH)2 produces 2 moles of NaOH. Therefore, the number of moles of NaOH produced is:2 * 0.0755 mol = 0.151 molFinally, we can convert the number of moles of NaOH to grams using its molar mass:0.151 mol * 40.00 g/mol = 6.04 gRounding to two decimal places, the theoretical yield of NaOH is 6.05 g. Therefore, the answer is option (C) 6.05 g.