Question

The width of a circular track is 2 meters. If the radius of the outer circle is 6 meters, find the area of the track.​

Answer 1

`62.8 \: {m}^(2)`

Explanation:

Radius of outer circle = 6 m

Width of the track = 2 m

So, radius of inner circle = 6 - 2 = 4 m

Area of the track = Area of outer circle - Area of inner circle

`= \pi {6}^(2) - \pi {4}^(2) \\ \\ = \pi( {6}^(2) - {4}^(2) ) \\ \\ = 3.14 * (36 - 16) \\ \\ = 3.14 * 20 \\ \\ = 62.8 \: {m}^(2)`