Question

Mass of crucible = l0g

Mass of crucible and soil before heating = 28g
Mass of crucible and soil after heating = 18g.
Determine the percentage of water in the given soil sample.

Thank you!​

Answer 1

Step-by-step explanation:

To determine the percentage of water in the soil sample, we need to find the mass of water lost during heating.

Mass of water lost = Mass of crucible and soil before heating - Mass of crucible and soil after heating

= 28g - 18g

= 10g

Now, we can calculate the percentage of water in the soil sample.

Percentage of water = (Mass of water lost / Mass of crucible and soil before heating) * 100

= (10g / 28g) * 100

= 35.71%

Therefore, the percentage of water in the given soil sample is approximately 35.71%.

hope it helps!

Answer 2

Mass of soil = (mass of crucible and soil after heating) - (mass of crucible) = 18g - 10g = 8g

Mass of water in soil = (mass of crucible and soil before heating) - (mass of crucible and soil after heating) = 28g - 18g = 10g

Percentage of water in soil = (mass of water in soil / mass of soil) x 100%

= (10g / 8g) x 100%

= 125%

Therefore, the percentage of water in the given soil sample is 125%. However, it is not possible to have more than 100% of a substance in a mixture. This result may indicate that there was an error in the measurements or calculations.