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1 Suppose the displacement of particle P from origin at time t is given by x(t)=t²-6t find the average velocity and acceleration of p over the time interval 1 <=t<=3 sec



User UDude
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1 Answer

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Answer:

-2 m/s and the average acceleration is 2 m/s².

Step-by-step explanation:

To find the average velocity of particle P over the time interval 1<=t<=3 sec, we need to use the following formula:

average velocity = (final displacement - initial displacement) / (final time - initial time)

In this case, the initial time is 1 sec and the final time is 3 sec. Therefore, the initial displacement is:

x(1) = 1² - 6(1) = -5

And, the final displacement is:

x(3) = 3² - 6(3) = -9

Now, we can substitute the values in the formula:

average velocity = (-9 - (-5)) / (3 - 1) = -2 m/s

To find the average acceleration of particle P over the time interval, we need to use the following formula:

average acceleration = (final velocity - initial velocity) / (final time - initial time)

We know that the initial time is 1 sec, the final time is 3 sec, and the initial velocity is the velocity at time t=1 sec. Therefore, the initial velocity is:

v(1) = 2t - 6 = 2(1) - 6 = -4 m/s

We also know that the final velocity is the velocity at time t=3 sec. Therefore, the final velocity is:

v(3) = 2t - 6 = 2(3) - 6 = 0 m/s

Now, we can substitute the values in the formula:

average acceleration = (0 - (-4)) / (3 - 1) = 2 m/s²

Therefore, the average velocity of particle P over the time interval 1<=t<=3 sec is -2 m/s and the average acceleration is 2 m/s².

User Talmid
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